Find the currents flowing around the following circuit using Kirchhoff's Current Law.
IT = Total current in the circuit
I1 current on path of R1
I2 current on path of R2
I3 current on path of R3
I1 = IT
I2 + I3 = I1
Total resistance in the circuit = 4 + 1(1/6 + 1/12)) = 4 + 4 = 8 Ohms
IT = 12/8 =